Comments on: issue in assingment 01 https://www.emblogic.com/blog/07/issue-in-assingment-01/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 By: hemant.kumar https://www.emblogic.com/blog/07/issue-in-assingment-01/#comment-910 Mon, 02 Jul 2012 19:25:11 +0000 http://emblogic.org/blog/?p=3765#comment-910 and x+=y+=z (+= assignment operator)
y=y+z;y=2
x=x+y;x=3

z+=x<y;
split it like…z=(z+x)<y (+ has higher priority then relational operator(<))
so you have to solve it first)

]]> By: hemant.kumar https://www.emblogic.com/blog/07/issue-in-assingment-01/#comment-909 Mon, 02 Jul 2012 19:20:44 +0000 http://emblogic.org/blog/?p=3765#comment-909 ?:it’s a TERNARY operator and applicable for single statement..
supppose you have two values x=9 and y=10
(x>y)?x:y then 10 will be printed ,it just behaves like your if-else
x+=y+=z

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