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	<title>Comments on: Solve the Mystery of pre and post increment operators</title>
	<atom:link href="https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/feed/" rel="self" type="application/rss+xml" />
	<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/</link>
	<description>Embedded System and ARM Training</description>
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		<title>By: arjumand</title>
		<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/#comment-811</link>
		<dc:creator><![CDATA[arjumand]]></dc:creator>
		<pubDate>Wed, 13 Jun 2012 16:53:20 +0000</pubDate>
		<guid isPermaLink="false">http://emblogic.org/blog/?p=3156#comment-811</guid>
		<description><![CDATA[hahaha..........its not possible to get the right answer at one go]]></description>
		<content:encoded><![CDATA[<p>hahaha&#8230;&#8230;&#8230;.its not possible to get the right answer at one go</p>
]]></content:encoded>
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		<title>By: Ram</title>
		<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/#comment-807</link>
		<dc:creator><![CDATA[Ram]]></dc:creator>
		<pubDate>Wed, 13 Jun 2012 12:44:29 +0000</pubDate>
		<guid isPermaLink="false">http://emblogic.org/blog/?p=3156#comment-807</guid>
		<description><![CDATA[but if we go accoring to precedence table the priority of k++ is higher than ++k]]></description>
		<content:encoded><![CDATA[<p>but if we go accoring to precedence table the priority of k++ is higher than ++k</p>
]]></content:encoded>
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	<item>
		<title>By: saurabh.aggarwal</title>
		<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/#comment-805</link>
		<dc:creator><![CDATA[saurabh.aggarwal]]></dc:creator>
		<pubDate>Tue, 12 Jun 2012 16:03:17 +0000</pubDate>
		<guid isPermaLink="false">http://emblogic.org/blog/?p=3156#comment-805</guid>
		<description><![CDATA[don&#039;t look it as denominator or numerator..
it is just an expression in c in which the priority of pre-increment is higher than that of post increment....]]></description>
		<content:encoded><![CDATA[<p>don&#8217;t look it as denominator or numerator..<br />
it is just an expression in c in which the priority of pre-increment is higher than that of post increment&#8230;.</p>
]]></content:encoded>
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	<item>
		<title>By: arjumand</title>
		<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/#comment-797</link>
		<dc:creator><![CDATA[arjumand]]></dc:creator>
		<pubDate>Mon, 11 Jun 2012 06:47:43 +0000</pubDate>
		<guid isPermaLink="false">http://emblogic.org/blog/?p=3156#comment-797</guid>
		<description><![CDATA[Why are u executing ++k(denominator) 1st???]]></description>
		<content:encoded><![CDATA[<p>Why are u executing ++k(denominator) 1st???</p>
]]></content:encoded>
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	<item>
		<title>By: sahil sharma</title>
		<link>https://www.emblogic.com/blog/06/solve-the-mystery-of-pre-and-post-increment-operators/#comment-793</link>
		<dc:creator><![CDATA[sahil sharma]]></dc:creator>
		<pubDate>Sun, 10 Jun 2012 15:36:07 +0000</pubDate>
		<guid isPermaLink="false">http://emblogic.org/blog/?p=3156#comment-793</guid>
		<description><![CDATA[before i give u solution,i will tell you how a post and preincrement work.
1.the operation is start from right to left and printing the value from left to right.
2.In preincrement first the value is increment then operation is performed and In postincrement first operation is performed then increment.
3.In postincrement the value is print after the operation is performed but in preincrement the value is print after all the operation is performed and print value from left to right.
qns1.assume the value of k is 1.
 d=k++/++k;
it means first value of k is 2 through ++k and now the value of k is 2,so d=2/2=1.
other problem u can solve easily through this rule...]]></description>
		<content:encoded><![CDATA[<p>before i give u solution,i will tell you how a post and preincrement work.<br />
1.the operation is start from right to left and printing the value from left to right.<br />
2.In preincrement first the value is increment then operation is performed and In postincrement first operation is performed then increment.<br />
3.In postincrement the value is print after the operation is performed but in preincrement the value is print after all the operation is performed and print value from left to right.<br />
qns1.assume the value of k is 1.<br />
 d=k++/++k;<br />
it means first value of k is 2 through ++k and now the value of k is 2,so d=2/2=1.<br />
other problem u can solve easily through this rule&#8230;</p>
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