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	<title>Comments on: query regarding Assignment1 question 13</title>
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	<link>https://www.emblogic.com/blog/06/query-regarding-assignment1-question-13/</link>
	<description>Embedded System and ARM Training</description>
	<lastBuildDate>Mon, 07 Oct 2013 04:00:03 +0000</lastBuildDate>
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		<title>By: hemant.kumar</title>
		<link>https://www.emblogic.com/blog/06/query-regarding-assignment1-question-13/#comment-886</link>
		<dc:creator><![CDATA[hemant.kumar]]></dc:creator>
		<pubDate>Sun, 01 Jul 2012 15:23:55 +0000</pubDate>
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		<description><![CDATA[range of signed integer is from -2147483648 to+2147483647....and for unsigned integer(+ve values)0 to 4294967295U..
when you increement it by 1 it goes back to the first value and so on.. but in case of unsigned integer if you add 1 to the maximum value it gives ZERO and it is represented by %u ..]]></description>
		<content:encoded><![CDATA[<p>range of signed integer is from -2147483648 to+2147483647&#8230;.and for unsigned integer(+ve values)0 to 4294967295U..<br />
when you increement it by 1 it goes back to the first value and so on.. but in case of unsigned integer if you add 1 to the maximum value it gives ZERO and it is represented by %u ..</p>
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		<title>By: Hemkaran</title>
		<link>https://www.emblogic.com/blog/06/query-regarding-assignment1-question-13/#comment-884</link>
		<dc:creator><![CDATA[Hemkaran]]></dc:creator>
		<pubDate>Sun, 01 Jul 2012 03:51:33 +0000</pubDate>
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		<description><![CDATA[coz 2147483647(2^32 -1) is the maximum value of a integer can accept. If u increament by 1 then it will round to starting value which is -2147483648(2^32).]]></description>
		<content:encoded><![CDATA[<p>coz 2147483647(2^32 -1) is the maximum value of a integer can accept. If u increament by 1 then it will round to starting value which is -2147483648(2^32).</p>
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