Comments on: problem in assingment 01

By: hemant.kumar

hemant.kumar — Sun, 01 Jul 2012 16:15:49 +0000

x=y=z=1;
++x (pre increement) it means x will be 2
here ||(logical or)
according to the compiler..it wont check further it it is true..so there will be no change in the values of y and z
your output will be 2,1,1
for instance…
x=-1,y=1,z=1;
then x,y,z will be 0,2,2
logical or(||) -> if the first statement is true(1) then it wont check it further
whereas logical(&&)–>it checks the whole statement.. here priority of these operators doesn’t matter..it goes from left to right

By: sandeep.kumar

sandeep.kumar — Thu, 28 Jun 2012 07:11:01 +0000

++x||++y&&++z

x gets preincremented to 2.
since logical or is evaluating to true in first expression(i.e. ++x) so rest of expression is not evaluated.

and the result is 2,1,1

By: himanshi

himanshi — Wed, 27 Jun 2012 19:57:42 +0000

im sorry actually i dint see properly…..
actually x will incremented before encountering || operator………

thnx

By: himanshi

himanshi — Wed, 27 Jun 2012 19:53:32 +0000

c first of all compiler will check the or operator as it has more priority than and gate then now in this case…it will execute from left
1st process x=1
then as soon as itll obtain or operator it ll incremt its value and then if it iz >0 it will directly give answr as 1… for the whole expression……….

but for x=2,y=1,z=1
thanx

By: himanshi

himanshi — Wed, 27 Jun 2012 19:52:30 +0000

thanx