Comments on: problem in assingment 01 https://www.emblogic.com/blog/06/problem-in-assingment-01-2/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 By: hemant.kumar https://www.emblogic.com/blog/06/problem-in-assingment-01-2/#comment-890 Sun, 01 Jul 2012 16:08:14 +0000 http://emblogic.org/blog/?p=3591#comment-890 priority order
& —> ^ —> |
if you find ~ ,then solve it first

]]> By: m siddarth https://www.emblogic.com/blog/06/problem-in-assingment-01-2/#comment-872 Fri, 29 Jun 2012 10:55:16 +0000 http://emblogic.org/blog/?p=3591#comment-872 Execution process from top:
x=03;y=02;z=01;
printf(“%d\n”,x|y&z);//evaluation is: (x | (y&z))
printf(“%d\n”,x|y&~z);//evalusation is: (x | (y & (~z)))
printf(“%d\n”,x^y&z);//evaluation is: (x ^ (y & z))
printf(“%d\n”,x&y&z);//evaluation is: ((x&y)&z)

x=1;y=-1;
printf(“%d\n”,!x|x);//evaluation is: ((!x) | x)
printf(“%d\n”,~x|x);//evaluation is: ((~x) | x)
printf(“%d\n”,x^x);// evaluation of XOR operation

x<<=3; printf("%d\n",x);// initialy x = 01 hence 01<<=3 results to 8
y<<=3; printf("%d\n",y);// initially y = -01 hence -01 <>=3; printf(“%d\n”,y);// initially y = -08 hence 08 >>= 3 results to -1

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