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	<title>Comments on: Plz Explain how to solve this question?</title>
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	<link>https://www.emblogic.com/blog/05/plz-explain-how-to-solve-this-question/</link>
	<description>Embedded System and ARM Training</description>
	<lastBuildDate>Mon, 07 Oct 2013 04:00:03 +0000</lastBuildDate>
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		<title>By: Tanvir Kumar</title>
		<link>https://www.emblogic.com/blog/05/plz-explain-how-to-solve-this-question/#comment-3953</link>
		<dc:creator><![CDATA[Tanvir Kumar]]></dc:creator>
		<pubDate>Fri, 24 May 2013 11:35:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.emblogic.com/blog/?p=6486#comment-3953</guid>
		<description><![CDATA[Thanks Vinod Khatana]]></description>
		<content:encoded><![CDATA[<p>Thanks Vinod Khatana</p>
]]></content:encoded>
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	<item>
		<title>By: vinod khatana</title>
		<link>https://www.emblogic.com/blog/05/plz-explain-how-to-solve-this-question/#comment-3952</link>
		<dc:creator><![CDATA[vinod khatana]]></dc:creator>
		<pubDate>Fri, 24 May 2013 10:07:21 +0000</pubDate>
		<guid isPermaLink="false">http://www.emblogic.com/blog/?p=6486#comment-3952</guid>
		<description><![CDATA[we can&#039;t use more than one, pre or post increment in one line,according to standard its give warning when prog. compile from command &quot;gcc -Wall que.c&quot;.Its should as give bellow and o/p = 100;
i=3;
    x = 1*a[--i];
    x = x+2*a[--i];
    x = x+3*a[--i];
    printf(&quot;%d\n&quot;,x);]]></description>
		<content:encoded><![CDATA[<p>we can&#8217;t use more than one, pre or post increment in one line,according to standard its give warning when prog. compile from command &#8220;gcc -Wall que.c&#8221;.Its should as give bellow and o/p = 100;<br />
i=3;<br />
    x = 1*a[--i];<br />
    x = x+2*a[--i];<br />
    x = x+3*a[--i];<br />
    printf(&#8220;%d\n&#8221;,x);</p>
]]></content:encoded>
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		<title>By: Tanvir Kumar</title>
		<link>https://www.emblogic.com/blog/05/plz-explain-how-to-solve-this-question/#comment-3951</link>
		<dc:creator><![CDATA[Tanvir Kumar]]></dc:creator>
		<pubDate>Fri, 24 May 2013 03:51:16 +0000</pubDate>
		<guid isPermaLink="false">http://www.emblogic.com/blog/?p=6486#comment-3951</guid>
		<description><![CDATA[But answer is 110???]]></description>
		<content:encoded><![CDATA[<p>But answer is 110???</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: rajnish</title>
		<link>https://www.emblogic.com/blog/05/plz-explain-how-to-solve-this-question/#comment-3949</link>
		<dc:creator><![CDATA[rajnish]]></dc:creator>
		<pubDate>Wed, 22 May 2013 06:45:16 +0000</pubDate>
		<guid isPermaLink="false">http://www.emblogic.com/blog/?p=6486#comment-3949</guid>
		<description><![CDATA[x=100;
initial value of i=3;
after--i=2
after--i=1
after--i=0
so the coresponding value is 30,20,10
s0 x=1*30+2*20+3*10=100]]></description>
		<content:encoded><![CDATA[<p>x=100;<br />
initial value of i=3;<br />
after&#8211;i=2<br />
after&#8211;i=1<br />
after&#8211;i=0<br />
so the coresponding value is 30,20,10<br />
s0 x=1*30+2*20+3*10=100</p>
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