Comments on: Problem with bit wise operators https://www.emblogic.com/blog/04/problem-with-bit-wise-operators/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 By: kpeswani https://www.emblogic.com/blog/04/problem-with-bit-wise-operators/#comment-737 Fri, 27 Apr 2012 11:44:36 +0000 http://emblogic.org/blog/?p=2364#comment-737 THERE IS SMALL ERROR IN PREVIOUS POST…Pls ignore it

num = num << 8;
the above line in char_pad() is of no use.

try this for bit representation..
int i=1;
int j;
for(j=0;j<16;j++)
{
if(num & i == 1)
printf("1\n");//or store 1
else
printf("0\n");
i<<=1;
}

]]> By: kpeswani https://www.emblogic.com/blog/04/problem-with-bit-wise-operators/#comment-736 Fri, 27 Apr 2012 11:43:29 +0000 http://emblogic.org/blog/?p=2364#comment-736 num = num << 8;
the above line in char_pad() is of no use.

try this for bit representation..
int i=1;
int j;
for(j=0;j<16;j++)
{
if(num & i == 1)
printf("1\n");//or store 1
else
printf("2\n");
i<<=1;
}

]]> By: nitin.sharma https://www.emblogic.com/blog/04/problem-with-bit-wise-operators/#comment-698 Tue, 10 Apr 2012 04:07:48 +0000 http://emblogic.org/blog/?p=2364#comment-698 In case of signed number,on 32 bit machine having integer length 4 bytes, MSB bit represents the sign.
in case of positive number it is zero and for negative number it is 1.

in my case i am trying to print bit representation of a number. and i am getting -1 instead of one even MSB is zero.

]]> By: msiddarth https://www.emblogic.com/blog/04/problem-with-bit-wise-operators/#comment-695 Sun, 08 Apr 2012 10:39:42 +0000 http://emblogic.org/blog/?p=2364#comment-695 could you elaborate more

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