https://www.emblogic.com/blog/02/3rd-printf-is-printing-4-why/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 https://www.emblogic.com/blog/02/3rd-printf-is-printing-4-why/#comment-629 Sat, 11 Feb 2012 06:41:28 +0000 http://emblogic.org/blog/?p=1940#comment-629 first y==z will be evaluated. here both y and z are equal to 4.
so it will return 1.
and x will be printed 1.

]]> https://www.emblogic.com/blog/02/3rd-printf-is-printing-4-why/#comment-627 Fri, 10 Feb 2012 13:29:26 +0000 http://emblogic.org/blog/?p=1940#comment-627 and what if i do x=y==z; then

]]> https://www.emblogic.com/blog/02/3rd-printf-is-printing-4-why/#comment-625 Fri, 10 Feb 2012 08:24:34 +0000 http://emblogic.org/blog/?p=1940#comment-625 As the statement
x=y=z; implies that the value in z has to be assign to y and x simultaneously. Hence, the value in x is 4 and correspondingly the printf statement will print 4.

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