Comments on: Project 01 https://www.emblogic.com/blog/01/project-01-4/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 By: Vikram Sharma https://www.emblogic.com/blog/01/project-01-4/#comment-3453 Sun, 20 Jan 2013 18:54:44 +0000 http://emblogic.org/blog/?p=5919#comment-3453 I understood your logic Sir, i too had same…But the result of expression ++x || ++y && ++z; (with x =-1).is not as this logic.

]]> By: rahul1989 https://www.emblogic.com/blog/01/project-01-4/#comment-3442 Sun, 20 Jan 2013 04:13:43 +0000 http://emblogic.org/blog/?p=5919#comment-3442 ++x && ++y || ++z
The above expression is evaluated on the basis of precedence order.

++(variable) > && (logical and) > || (logical or ) precedence order

It means that the expression is evaluated as ((++x && ++y ) || ++z))

let assign x =1, y = 2, z = 3
the expression is evaluated as

x = 2, y = 3, z = 3

Note that is NOT evaluated because
CASE 1
(value1) && (value2)
when value1 = 0, The result become 0 either another value2 = 0 or value2 = 1,
so compiler will NOT evaluate other value2 if left side value1 is 0,
the right side value is evaluated only if left side value1 is equal to 1.

CASE 2
(value1) || (value2)
when value1 = 1, The result become 0 either another value2 = 1 or value2 = 0,
so compiler will NOT evaluate other value2 if left side value1 is 1,
the right side value is evaluated only if left side value1 is equal to 0.

I hope you got understand.

]]> By: Deepak garg https://www.emblogic.com/blog/01/project-01-4/#comment-3424 Fri, 18 Jan 2013 12:41:00 +0000 http://emblogic.org/blog/?p=5919#comment-3424 I face same problem as u faced if U get the concept plz explain on the post.

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