https://www.emblogic.com/blog/01/1473/ Embedded System and ARM Training Mon, 07 Oct 2013 04:00:03 +0000 hourly 1 http://wordpress.org/?v=3.9.1 https://www.emblogic.com/blog/01/1473/#comment-498 Thu, 05 Jan 2012 12:13:48 +0000 http://emblogic.org/blog/?p=1473#comment-498 In second statement, value of z i.e 4 is assigned to y & x==4 returns false value & then x returns previous value stored in it,
This is due to exception handling & throw function in this compiler which prints previous stored value.
u can check it by removing statement x=y==z and then executing program.

]]> https://www.emblogic.com/blog/01/1473/#comment-486 Tue, 03 Jan 2012 14:01:01 +0000 http://emblogic.org/blog/?p=1473#comment-486 will u please explain

]]> https://www.emblogic.com/blog/01/1473/#comment-485 Tue, 03 Jan 2012 13:41:57 +0000 http://emblogic.org/blog/?p=1473#comment-485 why this x will return previous stored value in last statement when it is false in current statement?

]]> https://www.emblogic.com/blog/01/1473/#comment-483 Tue, 03 Jan 2012 08:58:34 +0000 http://emblogic.org/blog/?p=1473#comment-483 y==z returns 1 which is assigned to x therefore
x=1
x==(y=z) does no effect on value of x

]]> https://www.emblogic.com/blog/01/1473/#comment-482 Tue, 03 Jan 2012 08:56:58 +0000 http://emblogic.org/blog/?p=1473#comment-482 as y==z returns true value i.e 1 ,therefore this value is assigned to x ,hence x=1 in first expression,…
and in second one, value of z i.e 4 is assigned to y & x==4 returns false value therefore x returns previous value stored in it i.e 1……

]]> https://www.emblogic.com/blog/01/1473/#comment-481 Tue, 03 Jan 2012 08:44:55 +0000 http://emblogic.org/blog/?p=1473#comment-481 x=1;
x=1;

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