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PROGRAM TO PRINT 1BYTE FROM 4 BYTES OF INT
anubala331
August 2014
/*..PROGRAM TO PRINT 1BYTE FROM 4 BYTES OF INT..*/
#include<stdio.h>
int main()
{
int i=45678,j=0;/
/this is 32 bit system //so int is of 32 bits../
/
j=i;/
/PRESERVE VALUE IN J...BCZ IIN I ..WE ARE SHIFTING VALUE
i=i<<24;
//TO PRINT 1ST BYTE...FROM 32BITS ...MAKE 24 LEFT SHIFT & THEN 24 RIGHT SHIFT TO REMOVE ALL GARBAGE VALUES FROM THAT INT TYPE ..//
i=i>>24;
printf("1st byte of i=%d\n",i);
i=j;
i=i<<16;
//TO PRINT 2ND BYTE OF INT ...16 LEFT SHIFT & THEN 24 RIGHT ..MAKE 2ND BYTE AS LAST 8 BITS..BY REMOVING ALL GARBAGE..//
i=i>>24;
printf("2nd byte of i=%d\n",i);
i=j;
i=i<<8;//
TO PRINT 3RD BYTE OF INT ..BY MAKING 8 LEFT SHIFT & 24 RIGHT SHIFT..
i=i>>24;/
/SO BY MAKING ALL 3RD BYTE AS RIGHTMOST 8 BITS OF INT INTEGER BY REMOVING ALL GARBAGE
printf("3rd byte of i=%d\n",i);
i=j;
i=i>>24;/
/I SAME WAY,..4TH BYTE OF INT WHICH IS LEFTMOST 8 BITS OF 4 BYTE INT ...IN RIGHT SHIFTED 24...BY REMOVING ALL GARAGE..THIS WILL BE PRINTED
printf("4th byte of i=%d\n",i);
return 0;
}
anubala331
August 2014
OUTPUT:
[root@localhost]/home/c-asignments/ass# ./a.out
1st byte of i=110
2nd byte of i=-78
3rd byte of i=0
4th byte of i=0
[root@localhost]/home/c-asignments/ass#
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