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//A NICE IMPLEMENTATION TO TURN ON A BIT
anubala331
August 2014
//A NICE IMPLEMENTATION TO TURN ON A SINGLE BIT IN BYTE OF CHAR//
//kth bit starts from right hand side//
//kth power of 2 will on that periticular bit..
//for eg.0th bit....0000 0001
//for eg.1th bit....0000 0010
//for eg.2th bit....0000 0100
//for eg.3th bit....0000 1000
//for eg.4th bit....0001 0000
//for eg.5th bit....0010 0000
//for eg.6th bit....0100 0000
//for eg.7th bit....1000 0000
//
#include<stdio.h>
int main()
{
int get,rem[20]={0},i=0,j=0,no=0,k=0;
printf("ENTER THE kTH BIT U WANT TO TURN ON:\n");
scanf("%d",&k);
k--;
//decrement k once//
get=power(k);
//get power of k..//
printf("get=%d\n",get);
no=no | get;/
/no=0 already...now kth power of 2 is ored with no..////
while(no!=0)
{
rem[i]=rem[i]*10;
//no use //to get into binary representation//
rem[i]=no%2;/
/get remainder of number...//
no=no/2;/
/divide number by 2//
i++;
}
for(j=(i-1);j>=0;j--)/
/representation of this number into reverse order will print its binary representation//
printf("%d",rem[j]);
return 0;
}
int power(int k)
{
int a=2,i=0;/
/a=2 means i have to find kth(power of 2)
if(k==0)
return 1;/
/if 0th power(2)..then it is always 1
else if(k>0)/
/else
{
for(i=1;i<k;i++)/
/loop is operated in which a is modified everytime..//by multiplying 2...each time to getkth power of 2...
a=2*a;/
/2
}
return a;//
return that powered value..//
}
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