/*AN IMPLEMENTATION TO REVERSE A NO.*/

/*AN IMPLEMENTATION TO REVERSE A NO.*/

#include<stdio.h>

int main()

{

int num=0,r=0;

printf("ENTER THE NO: TO REVERSE\n");//suppose no. is 4576//enter the no. to reverse

scanf("%d",&num);

//AS NO.DIVIDED BY 10 EVERY TIME ..//A NEW REMAINDER WILL FOUND TO U...THAT NEW REMAINDER IS ADDED TO PREVIOUS r BY MULTIPLYING IT TO 10//EVERYTIME ......FINALLY WHEN  NUMBER WHOSE REVERSE IS TO FIND WILL BECOME 0...MEANS ALL DIGITS OF THIS NUMBER ARE  REVERSED. ALREADY..//

while(num != 0)//remains into loop untill num becomes 0

{

r=r*10;//60//670//6750....//

r=r+(num%10);//60+7=67//670+5=675//6750+4=6754..net reversed no..//

num=num/10;//457//45//4..in three iterations of loop for 4 characters in no. ..no. is reversed..//

}

printf("reverse no.=%d\n",r);

return 0;

}

~